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Solve the following quadratic equation:

ix2 – 4x – 4i = 0

1 Answer

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Best answer

ix2 – 4x – 4i = 0

Multiplying throughout by i, we get

i2x2 – 4ix – 4i2 = 0

-x2 – 4ix + 4 = 0 …[∵ i2 = -1]

x2 + 4ix – 4 = 0

Comparing with ax2 + bx + c = 0, we get

a = 1, b = 4i, c = -4

Discriminant = b2 – 4ac

= (4i)2 – 4 × 1 × (-4)

= 16i + 16

= -16 + 16

= 0

So, the given equation has equal roots.

These roots are given by

∴ The root of the given equation is -2i.

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