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1 Answer

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by (10.9k points)
edited by
Let x^2= secu

So 2xdx = secutanudu

Now  

I = integration (secutanudu/[(1-secu)×tanu]

=-Integration(du/(1-cosu)

=--Intgration(du/(2sin^2(u/2))

=-1/2Integrationcsc^2(u/2)du

=1/2×2cot(u/2)+c

=cot(u/2) +c

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