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In a triangle, ABC, ∠BAC = 90°; AD is the altitude from A onto BC. Draw DE perpendicular to AC and DF perpendicular to AB. Suppose AB = 15 and BC = 25. Then the length of EF is

(a) 12

(b) 0

(c) 5√3

(d) 5√5

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The correct option is (a) 12.

AEDF is Rectangle then AD = EF = 12

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