Question

Let, n ≥ 1, be an arithmetic progression with first term 2 and common difference 4. Let M_n be the average of the first n terms. Then the sum ∑_n=1¹⁰ M_n = 

(a) 110

(b) 335

(c) 770

(d) 1100

Answer 1

The correct option is (a) 110.

A.P  a_n​  n ≥ 1

First term a₁​ = 2

Common difference d = 4

M_n​ =  Average of first n terms.