Question

Let a, b, c, d be distinct real numbers such that a, b are roots of x² – 5cx – 6d = 0, and c, d are roots of x² – 5ax – 6b = 0. Then b + d is:- 

(a) 180

(b) 162

(c) 144

(d) 126

Answer 1

The correct option is (c) 144.

Here, a and b are roots of the equation x² − 5cx − 6d = 0

Now, c and d are roots of the equation x² − 5ax − 6d = 0

Substituting value of a + c in equation (5) we get,

⇒ b + d = 4(36)

∴ b + d = 144