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Let a, b, c, d be distinct real numbers such that a, b are roots of x2 – 5cx – 6d = 0, and c, d are roots of x2 – 5ax – 6b = 0. Then b + d is:- 

(a) 180

(b) 162

(c) 144

(d) 126

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The correct option is (c) 144.

Here, a and b are roots of the equation x− 5cx − 6d = 0

Now, c and d are roots of the equation x− 5ax − 6d = 0

Substituting value of a + c in equation (5) we get,

⇒ b + d = 4(36)

∴ b + d = 144

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