Cube root of ​ √4 + √36 is ​

Question

Cube root of  √4 + \(\sqrt{36}\) is 

A) \(\sqrt[3]{144}\)

B) 8 

C) 2 

D) \(\sqrt[3]{40}\)

Answer 1

Correct option is (C) 2

\(\sqrt{4}+\sqrt{36}\) = 2+6 = 8

Cube root of \(\sqrt{4}+\sqrt{36}\) is \((\sqrt{4}+\sqrt{36})^\frac13\)

\(=(8)^\frac13=(2^3)^\frac13=2\)

Answer 2

Correct option is  C) 2