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0 votes
3.3k views
in Physics by (15 points)
edited by

A ball is thrown vertically upwards with velocity 10 m/s from a trolley moving horizontally with velocity of 8 m/s. A person standing on ground observe its motion. The range observed by him is (g = 10m/s).

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2 Answers

+2 votes
by (223 points)

Vertical velocity of ball  uy​=v1​

Horizontal velocity of ball  ux​=v2​

Horizontal range of projectile   R=2ux​uy​​/g

⟹ R=

2v1​v2​​/g = 2* 10*8/ 10= 16 m

+2 votes
by (32.0k points)

Horizontal velocity of ball is trolley

S = uHt

R = uHt

Sg = ugt - \(\frac12\)agt2

Sy = 0

uyt - \(\frac12\)gt2 = 0

uyt = \(\frac12\)gt2

uy = \(\frac{gt}2\)

t = \(\frac{2u_y}g\) 

t = \(\frac{2\times10}{10}\) 

t = 2 sec

Range observed by him is

Given uH = 8m/s

R = uHt

R = 8 x 2

R = 16 m

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