**Distance (in m)** |
0 - 1 |
1 – 2 |
2 - 3 |
3 - 4 |
4 - 5 |

**Number of Students** |
40 |
80 |
62 |
38 |
30 |

**cf** |
40 |
120 |
182 |
220 |
250 |

\(\frac{n}{2}=\frac{250}{2}\) = 125

⇒ median class is 2 - 3, l = 2, h = 1, cf = 120, f = 62

median = \(l+\frac{\frac{n}{2}-cf}{f}\times i\)

= 2 + \(\frac{5}{62}\)

= \(\frac{129}{62}=2\frac{5}{62}\)m or 2.08 m

50% of students jumped below \(2\frac{5}{62}\)m and 50% above it.