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in JEE by (3.3k points)
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∫ dx / √sin^3x sin(x+a) ; a≠nπ, n∈Z

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by (7.2k points)
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Best answer

sin3x sin(x+a)
= sin4x[cos a + cot x sin a]   {use si(a +b)}

so we can write integration as 

let cos a + cot x sin a = t
- cosec2x sin a dx= dt
cosec2x dx= 1/ sin a dt
Now put in the equation 

put the value and you will get 

by (3.3k points)
thanks.........

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