**The Capacitance of big drop will be 20μF**

We have,

Volume of big drop = 64 times the volume of small drop

or 4/3 π.R^{3} = 64 x 4/3 π.r^{3}

Or R = 4r

Now, we know that the capacitance for a solid spherical body is directly proportion to radius of the solid sphere

Then,

Capacitance of big drop

= 4 x capacitance of small drop

= 4 x 5

= 20μF