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64 identical small drops combine to form a big drop. Calculate the capacity of big drop if capacity of each small drop is 5 mF.

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The Capacitance of big drop will be 20μF

We have,

Volume of  big drop = 64 times the volume of small drop

or 4/3 π.R3 = 64 x 4/3 π.r3

Or  R = 4r

Now, we know that  the capacitance for a  solid spherical body is directly proportion to radius of the solid sphere

Then,

Capacitance of big drop

= 4 x capacitance of small drop

= 4 x 5

= 20μF

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