Correct option is (A) \(\sqrt[3]{3}\)
\(\sqrt[3]{9}=(9)^\frac13=(3^2)^\frac13=(3)^\frac23\)
\(\because\) \((3)^\frac23\times(3)^\frac13=3^{(\frac23+\frac13)}\) \(=3^1=3\) which is a rational number.
i.e., \(\sqrt[3]{9}\times\sqrt[3]{3}=3\) a rational number.
It implies \(\sqrt[3]{3}\) is a rationalising factor of \(\sqrt[3]{9}.\)