Given equation is x2 – (3√2 + 2i) x + 6√2 i = 0
Comparing with ax2 + bx + c = 0, we get
a = 1, b = -(3√2 + 2i), c = 6√2i
Discriminant = b2 – 4ac
= [-(3√2 + 2i)]2 – 4 × 1 × 6√2 i
= 18 + 12√2i + 4i2 – 24√2 i
= 18 – 12√2 i – 4 ……[∵ i2 = -1]
= 14 – 12√2 i
So, the given equation has complex roots. These roots are given by
Equating real and imaginary parts, we get