Question

A particle has initial velocity vector (2i +3j) and acceleration vector (0.3i+0.2j).The magnitude of velocity after 10 seconds will be

(a) 9√2 units

(b)  5√2 units

(c) 5 units

(d) 9 units

Answer 1

Correct option  (b)  5√2 units

Explanation:

Answer 2

Option (b) is correct

Velocity vector after 10 s

= Initial vel vector + acceleration vector × time

= 2i+3j+(0.3i+0.3j×10=5i+5j

So magnitude of velocity

= √(5^2+5^2)=5√2 units