B = B1 + B2
B = \(\frac{HoI}{2\pi d}+\frac{HoI}{2\pi\,d/\sqrt3}\)
B = \(\frac{HoI}{2\pi}(\frac1d+\frac{\sqrt3}d)\)
Applying ampere's law:
\(\frac{HoI}{2\pi}(\frac{\sqrt3+1}d)\times\frac{2\pi d}{\sqrt3}=\frac{HoI}n\)
\(\frac{\sqrt3+1}{\sqrt3}=\frac1n\)
n = \(\frac{\sqrt3}{\sqrt3+1}\)