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in Binomial theorem by (160 points)
edited by

Show that nC0.nC0 - n+1C1.nC1 + n+2C2.nC2-....=(-1)n.

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1 Answer

+3 votes
by (33.2k points)

nC0.nC0 - n+1C1.nC1 + n+2C2.nC2 - .... is coefficient of xn in

(nC0(x + 1)n - nC1(x + 1)n+1 + nC2(x + 1)n+2-.....)

Now, nC(x + 1)n - nC1(x + 1)n+1 + nC2(x + 1)2-.....

= (x + 1)(nC0 - nC1(x + 1) + nC2(x + 1)2 -....)

= (x + 1)n (1 - (x + 1)n) (\(\because\) (1 - x)n = nC0- nC1x + nC2x2-....)

= (-x)n (x + 1)n

= (-1)n xn (x +1)n

Hence, Coefficient of xn in (nC0(x + 1)n - nC1(x + 1)n+1 + nC2(x+1)2) is (-1)n

\(\therefore\) nC0.nC0 - n+1C1.nC1 + n+2C2.nC2-....=(-1)n

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