Correct option is (D) 5.5
n = 10 = even
\(\therefore\) Median = Average of \(\frac n2th\) and \((\frac n2+1)th\) observations in ascending order.
= Average of \(5^{th}\) and \(6^{th}\) observations \((\because\) n = 10)
\(=\frac{5+6}2=\frac{11}2\)
= 5.5