The correct option is (B) 4 : 1.
I1 = 1
I2 = 9
Imax = (√I2 + √I1)2
Imin = (√I2 - √I1)2
\(\frac{I_{max}}{I_{min}}=\frac{(\sqrt{I_2}+\sqrt{I_1})^2}{(\sqrt I_2-\sqrt I_1)^2}\)
\(\frac{I_{max}}{I_{min}}=\frac{(\sqrt{9}+\sqrt{1})^2}{(\sqrt 9-\sqrt 1)^2}\)
\(\frac{I_{max}}{I_{min}}=\frac{(3+1)^2}{(3-1)^2}\)
\(\frac{I_{max}}{I_{min}}=\frac{(4)^2}{(2)^2}\)
\(\frac{I_{max}}{I_{min}}=\frac{16}{4}\)
\(\frac{I_{max}}{I_{min}}=\frac4{1}\)