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in Trigonometry by (15 points)
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1 Answer

+1 vote
by (420 points)
In the given figure,

PQ is parallel to AC (Since, PQ is the line of sight and AC is ground)

PC is a transversal cutting PQ and AC.

Angle PCA = Angle QPC (Alternate interior angles)

Angle QPC = 45°

Therefore, the angle of depression from point P to C is 45°.

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