Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
249 views
in Number System by (270 points)
edited by

Subtract:

4x by x- 1 - x + 1 by x - 1.

Please log in or register to answer this question.

1 Answer

+1 vote
by (36.7k points)

\(\frac{4x}{x^2-1}-\frac{x+1}{x-1}\)

\(=\frac{4x-(x+1)^2}{x^2-1}\)

\(=\frac{4x-(x^2+2x+1)}{x^2-1}\) 

\(=\frac{-(x^2+2x+1-4x)}{x^2-1}\)

\(=-\frac{x^2-2x+1}{x^2-1}\) 

\(=-\frac{(x-1)^2}{x^2-1}\) 

\(=\frac{(x-1)^2}{1-x^2}\)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...