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in Sets, Relations and Functions by (339 points)
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In a senior secondary school,80 students play football or hockey. The number that plays football is 5 more than twice the number that plays hockey. If 15 students play both games and every student in the school plays at least one game, find (i)the number of students that play football (ii)the number of students that play football but not hockey (iii)the number of students that play hockey but not football. It 

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by (6.0k points)
edited by
 
Best answer
Let the no of students who play hockey = x

No of students who play football = 2x + 5

No of students who play both hockey and football = 15

ATQ,

x + 2x + 5 -15 = 80

3x - 10 = 80

3x = 90 ∴ x = 30

No of students who play football = 2 × 30 + 5 = 65

Hence, 30 students play hockey, 65 play football and 15 play both.

(i) 65 students play football

(ii) No of students who play football but not hockey = 65 - 15 = 50

(iii) No. of students who play hockey but not football. = 30 - 15 = 15
by (339 points)
+1
I thought F or H = 80 is giving by
n(F u H) = n(F) + n(H) - n(F n H)
by (6.0k points)
edited by
Sorry i didn't read the or word in your question. I will just correct it. I assumed that 80 students play hockey and football.
by (6.0k points)
Thanks for reminding me. Now your doubt is cleared.
by (6.0k points)
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If you have doubt in any working of mine. You can still ask .
by (339 points)
+1
Thank i appreciate ur ans and ur wiill to ans my questions

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