# In the figure, OM AB and AM = 6 cm where ‘O’ is the centre of the circle then AB =

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In the figure, OM AB and AM = 6 cm where ‘O’ is the centre of the circle then AB =

A) 6 cm

B) 12 cm

C) 3 cm

D) 6 √6 cm

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Correct option is (B) 12 cm

We know that perpendicular from centre of the circle on any chord bisects the chord.

Since, OM $\bot$ AB

$\therefore$ OM bisect chord AB

$\Rightarrow$ M is mid-point of chord AB

$\Rightarrow$ AB = 2AM

$=2\times6$   $(\because$ AM = 6 cm)

= 12 cm

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Correct option is  B) 12 cm