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In the figure, OM AB and AM = 6 cm where ‘O’ is the centre of the circle then AB =

A) 6 cm 

B) 12 cm 

C) 3 cm 

D) 6 √6 cm

2 Answers

+1 vote
by (56.9k points)
selected by
Best answer

Correct option is (B) 12 cm

We know that perpendicular from centre of the circle on any chord bisects the chord.

Since, OM \(\bot\) AB

\(\therefore\) OM bisect chord AB

\(\Rightarrow\) M is mid-point of chord AB

\(\Rightarrow\) AB = 2AM

\(=2\times6\)   \((\because\) AM = 6 cm)

= 12 cm

+1 vote
by (42.4k points)

Correct option is  B) 12 cm

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