Question

In the given figure, ‘O’ is the centre of the circle and OP ⊥ AB. If AP = 6 cm, then AB =

A) 3 cm 

B) 9 cm 

C) 12 cm 

D) 18 cm

Answer 1

Correct option is (C) 12 cm

Perpendicular drawn from the centre of the circle to a chord is bisect the chord.

Since, OP \(\bot\) AB and O is centre of the circle

\(\therefore\) OP bisects AB

\(\therefore\) AP = PB

But AP+PB = AB

\(\therefore\) AB = 2AP

\(=2\times6\)    \((\because\) AP = 6 cm (given))

= 12 cm

Answer 2

Correct option is  C) 12 cm