Correct option is (A) 105/34
\(\frac{-2}{7}\times \frac{-17}{15}\) \(=\frac{-2\times-17}{7\times15}\) \(=\frac{34}{105}\)
\(\therefore\) Multiplicative inverse of \(\frac{-2}{7}\times \frac{-17}{15}\) is \(\cfrac1{\frac{34}{105}}\) \(=\frac{105}{34}.\)