Correct option is (D) ₹ 680
Let cost price of radio be Rs x.
\(\therefore\) Selling price = x + 10% of x
= x + \(\frac{10x}{100}\) = x + \(\frac{x}{10}\) \(=\frac{11x}{10}.\)
Given that selling price = Rs 748
\(\therefore\) \(\frac{11x}{10}=748\)
\(\Rightarrow\) \(x=\frac{748}{11}\times10=680\)
\(\therefore\) Cost price of that radio is Rs 680.
