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In the parallelogram ABCD the area of ΔABC is 10 sq.cm then the area of ABCD = ………………. sq.cm

A) 15 

B) 40 

C) 20 

D) 10

2 Answers

+1 vote
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Best answer

Correct option is (C) 20

In parallelogram ABCD, AC is a diagonal.

\(\because\) area of \(\triangle ABC\) = area of \(\triangle ACD\)

Also, area of \(\triangle ABC\) + area of \(\triangle ACD\) = area of rectangle ABCD.

\(\therefore\) Area of rectangle ABCD \(=2\times\) Area of \(\triangle ABC\)

\(=2\times10\,cm^2\)

\(=20\,cm^2\)

+2 votes
by (42.4k points)

Correct option is  C) 20

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