Correct option is (A) \(\frac{16}{225}\)
\((\frac{-3}{2})^{-4}\times(\frac{-3}{5})^2\) \(=\left[(\frac{-3}{2})^{-1}\right]^4\times(\frac{-3}{5})^2\)
\(=(\frac{-2}{3})^{4}\times(\frac{-3}{5})^2\)
\(=\frac{(-2)^4}{3^4}\times\frac{(-3)^2}{5^2}\)
\(=\frac{16}{81}\times\frac9{25}\)
\(=\frac{16}{9\times25}=\frac{16}{225}\)