Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE

Please log in or register to answer this question.

1 Answer

+1 vote
by (1.4k points)

The equation of families of straight lines passing through origin is y = ax, where a is arbitrary constant.

y = ax ....(1)

Differentiate equation (1) w.r.t x, we get

\(\frac{dy}{dx} = a\)

put \(a = \frac{dy}{dx}\) in equation (1), we get

\(y = x\frac{dy}{dx}\)

\(\Rightarrow x\frac{dy}{dx} - y = 0 ....(2)\)

Equation (2) represent the differential equation of the family of lines through the origin.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...