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in Chemistry by (74.5k points)

Bond dissociation enthalpy of H2, Cl2 and HCl are 434, 242 and 431 kJ mol -1 respectively. Enthalpy of formation of HCl is

(a) -93 kJ mol-1

(b) 245 kJ mol-1

(c) 93 kJ mol-1 

(d) -245 kJ mol-1

1 Answer

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Best answer

The correct option is: (a) -93 kJ mol-1

Explanation:

Heat of formation is the amount of heat absorbed or evolved when one mole of substance is directly obtained from its constituent element.

Hence, enthalpy of formation of HCI = -186/2 kJ

= -93 kJ mol-1

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