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0 votes
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in Cubes And Cube Roots by (38.9k points)

a + b + c = 0 then a3 + b3 + c3 = ………………

A) \(\frac{abc}{3}\)

B) 3 abc 

C) ab+c 

D) \(\frac{ab}{c}\)

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2 Answers

+1 vote
by (36.7k points)

Correct option is  B) 3 abc

+1 vote
by (57.0k points)

Correct option is (B) 3 abc

Since, \(a^3+b^3+c^3\) - 3ab \(=(a+b+c)(a^2+b^2+c^2-bc-ca-ab)\)

\(\therefore\) If a + b + c = 0, then \(a^3+b^3+c^3\) = 3 abc.

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