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The percentage of pyridine (C5H5N) that forms pyridinium ion (C5H5NH or  in a 0.10 M aqueous pyridine solution (Kb for C5H5N = 1.7 x 10-9) is

(a) 0.0060%

(b) 0.013%

(c) 0.77%

(d) 1.6%

1 Answer

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Best answer

The correct option is : (b) 0.013%

Explanation:

. .. Percentage of pyridine that forms pyridinium ion = 1.30 x 10-4 x 100 = 0.013%

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