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in Complex Numbers by (44.0k points)
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If n is an odd positive integer, then the value of 1 + (i)2n + (i)4n + (i)6n is:

(A) -4i

(B) 0

(C) 4i

(D) 4

1 Answer

+1 vote
by (44.0k points)
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Best answer

(B) 0

1 + (i2)n + (i4)n + (i2)3n

= 1 – 1 + 1 – 1 …..(n odd positive integer)

= 0

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