Fewpal
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in Mathematics by (127k points)
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Find the sum of the first 40 positive integers divisible by 6.
by (11.6k points)
edited by
+1
The answer should be 4920

2 Answers

+3 votes
by (21.1k points)
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Best answer

Solution:

the first 40 positive integers divisible by 6 are 6,12,18,....... upto 40 terms

the given series is in arthimetic progression with first term a=6 and common difference d=6

sum of n terms of an A.p is 

n/2×{2a+(n-1)d}

→required sum = 40/2×{2(6)+(39)6}

=20{12+234}

=20×246

=4920

+1 vote
by (11.6k points)
edited by
The answer is 4920

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