Question

The binding energy per nucleon in deuterium and helium nuclei are 1.1 MeV and 7.0 MeV, respectively. When two deuterium nuclei fuse to form a helium nucleus the energy released in the fusion is

(a) 23.6 MeV

(b) 2.2 MeV

(c) 28.0 MeV

(d) 30.2 MeV

Answer 1

The correct option is (a) 23.6 MeV.

Explanation:

The binding energy per nucleon of a deuteron = 1.1 MeV

Total binding energy = 2 x 1.1 = 2.2 MeV

The binding energy per nucleon of a helium nuclei =7 MeV

Total binding energy = 4 x 7 = 28 MeV

Hence, energy released