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AlF3 is soluble in HF only in presence of KF. It is due to the formation of

(a) K3[AlF3H3]

(b) K3[AlF6]

(c) AlH3

(d) K[AlF3H]

1 Answer

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Best answer

The correct option is: (b) K3[AlF6]

Explanation:

AlF3 is insoluble in anhydrous HF because the F- ions are not available in hydrogen bonded HF but, it becomes soluble in presence of little amount of KF due to formation of complex,

K3[AlF6].AlF3 + 3KF → K3[AlF6]

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