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300 J of work is done in sliding a 2 kg block up an inclined plane of height 10 m.

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300 J of work is done in sliding a 2 kg block up an inclined plane of height 10 m. Work done against friction is (Take g = 10 m/s2)

(a) 1000 J

(b) 100 J

(c) 100 J

(d) zero

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1 Answer

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Best answer

Correct option (c) 100 J

Explanation:

: Loss in potential energy  = mgh

= 2 x 10 x 10 = 200 J

Gain in kinetic energy: work done = 300 J

Work done against friction = 300 - 200 = 100 J

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