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What will be the minimum pressure required to compress 500 dm3 of air at 5 bar to 200 dm3 at 25 °C.

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Given: P1 = Initial pressure = 5 bar

V1 = Initial volume = 500 dm3 ; V2 = Final volume = 200 dm3

To find: P2 = Final pressure

Formula: P1 V1 = P2 V2 (at constant n and T)

Calculation: According to Boyle’s law

P1 V1 = P2 V(at constant n and T)

∴ P\(\frac{P_1V_1}{V_2}\) = \(\frac{5 \times 500}{200}\) = 12.5 bar

The minimum pressure required to compress 500 dm3 of air at 5 bar to 200 dm3 at 25 °C is 12.5 bar.

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