As we know that charge of an electron is given by **(q) = 1.6 x 10**^{-19} C

The potential difference is given here **(V) =** **10 V**

**KE**_{electron} = q x V = 1.6 x 10^{-19} x 10 = 1.6 x 10^{-18}

Linear Kinetic Energy of a gas is given by **3/2 KT** where K is Boltzman constant(R/N = 1.38 x 10^{-23})

**KE**_{Gas} = 3/2 (1.38 x 10^{-23})(T)

Now we equate both the equation:

3/2 (1.38 x 10^{-23})(T) = 1.6 x 10^{-18}

**T = 7.72 x 10**^{5} K

**At ****7.72 x 10**^{5} K temperature linear kinetic energy of a gas molecule will be equal to that of the electron.