# Show that the equilibrium constant of the reverse chemical reaction (Kc) is the reciprocal of the equilibrium constant (Kc).

104 views

closed

Show that the equilibrium constant of the reverse chemical reaction (Kc) is the reciprocal of the equilibrium constant (Kc).

+1 vote
by (34.8k points)
selected by

Consider a reversible chemical reaction: aA + bB ⇌ cC + dD

The equilibrium constant, Kc$\frac{[C]^c [D]^d}{ [A]^a [B]^b}$

Consider the reverse reaction:

cC + dD ⇌ aA + bB.

The equilibrium constant, Kc is:

Kc = $\frac{[A]^a [B]^b}{ [C]^c [D]^d}$ = $\frac{1}{K_c}$

Thus, equilibrium constant of the reverse chemical reaction (Kc) is the reciprocal of the equilibrium constant Kc