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Calculate Kc at 500 K for the reaction, 2HI(g) ⇌ H2(g) + I2(g) if the equilibrium concentrations are [HI] = 0.5 M, [H2] = 0.08 M and [I2] = 0.062 M.

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Given: T = 500 K,

At equilibrium, [HI] = 0.5 M, [H2] = 0.08 M, [I ] = 0.062 M.

To find: Equilibrium constant Kc

Formula: K = \(\frac{[C]^c [D]^d}{[A]^a [B]^b}\)

Calculation: The above equilibrium reaction is given as 2HI(g) ⇌ H2(g) + I2(g)

The expression of Kc is

Kc at 500 K for the given reaction is 0.0198.

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