Question

A particle executes linear simple harmonic motion with an amplitude of 3 cm. When the particle is at 2 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is

(a) √5/2π

(b) 4π/√5

(c) 2π√3

(d) √5/π

Answer 1

Correct option (b) 4π/√5

Explanation:

Given,A =3 cm,x= 2 cm

The velocity of a particle in simple harmonic motion is given as

and magnitude of its acceleration is