2H2(g) + O2(g) ⇌ 2H2O(g) is 2.4 × 10^47 at 500 K. What is the value of equilibrium constant for the reaction:2H2O(g) ⇌ 2H2(g) + O2(g) ?

Question

The equilibrium constant value for the reaction:

2H_2(g) + O_2(g) ⇌ 2H₂O_(g) is 2.4 × 10⁴⁷ at 500 K. What is the value of equilibrium constant for the reaction:2H₂O_(g) ⇌ 2H_2(g) + O_2(g) ?

(A) 0.41 × 10^-46

(B) 0.41 × 10⁴⁷ 

(C) 0.41 × 10^-48

(D) 0.41 × 10^-47 

Answer 1

(D) 0.41 × 10^-47