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0 votes
23.9k views
in Thermodynamics by (79.3k points)
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An ideal gas heat engine operates in a Carnot cycle between 227°C and, 127°C. It absorbs 6 k cal at the higher temperature. The amount of heat (in k cal) converted into work is equal to

(a) 4.8

(b) 3.5

(c) 1.6

(d) 1.2

2 Answers

+1 vote
by (76.4k points)
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Best answer

Correct option (d) 1.2

Explanation:

 Efficiency of Carnot engine

+1 vote
by (5.0k points)

We have QT = consta nt ⇒ Q2/Q1 = T2/T1

Given, 

Q1 = 6×104 cal,

T1 = 227+ 273 = 500K

T2 = 127 + 273 = 400K

= 1.2 

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