First we can select 7 objects out of 30 for the first group in 30C7 ways.
Now there are 23 objects left out of which we can select 10 objects for the second group in 23C10 ways.
Remaining 13 objects can be selected for the third group in 5C5 ways.
∴ Required number of ways = 30C7 x 23C10 x 13C13