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in Binomial Theorem by (44.1k points)
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Without expanding, find the value of

(x + 1)4 – 4(x + 1)3 (x – 1) + 6(x + 1)2 (x – 1)2 – 4(x + 1) (x – 1)3 + (x – 1)4

1 Answer

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by (44.2k points)
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Best answer

Let x + 1 = a and x - 1 = b

We notice that 1, 4, 6, 1 are the values of 4C0, 4C1, 4C2, 4C3, 4C4 respectively.

\(\therefore\) The given expression becomes

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