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in Binomial Theorem by (44.1k points)
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Without expanding, find the value of

(2x – 1)4 + 4(2x – 1)3 (3 – 2x) + 6(2x – 1)2 (3 – 2x)2 + 4(2x – 1)1 (3 – 2x)3 + (3 – 2x)4

1 Answer

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by (44.2k points)
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Best answer

Let 2x - 1 = a and 3 - 2x = b

We notice that 1, 4, 6, 4, 1 are the values of 4C0, 4C1, 4C2, 4C3, 4C4 respectively.

\(\therefore\) The given expression becomes

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