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Find the middle terms in the expansion of (x4 - 1/x3)11

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Here, a  = x4, b = -1/x3, n = 11

Now, n is odd

\(\therefore\) Middle terms are t6 and t7; for which r = 5 and r = 6 respectively.

We have tr+1 = nCr an-rbr

= 462x2

\(\therefore\) Middle terms are -462x9 and 462x2.

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