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0 votes
1.1k views
in Binomial Theorem by (44.2k points)
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Show that C1 + C2 + C3 + ….. + C7 = 127

2 Answers

+1 vote
by (44.1k points)
selected by
 
Best answer

Since C0 + C1 + C2+ C3 + ….. + Cn = 2n

Putting n = 7, we get

C0 + C1 + C2 + ….. + C7 = 27

∴ C0 + C1 + C2 +….. + C7 = 128

But, C0 = 1

∴ 1 + C1 + C2 + ….. + C7 = 128

∴ C1 + C2 + ….. + C7 = 128 – 1 = 127

+1 vote
by (20 points)
We know that,

C 0 +C 1 +C 2 +...+C n =2^ n

Put n = 7 , we get,

C 0 +C 1 +C 2 +...+C 7 =2^ 7 =128

therefore1+C 1 +C 2 +...+C 7 =128 ...[:^ n C 0

=1]

therefore C 1 +C 2 +C 3 +...+C 7 =127

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