Question

The ionization  energy of Li++ is equal to

A) 9hcR

B) 6hcR

C) 2hcR

D) hcR

Please  provide  the information  which formulae  of ionization  energy  is used here??

Answer 1

Option A is correct

Explanation

Equation used

∆E=Z^2hcR[1/n1^2-1/n2^2]

Where

∆E ->energy required for promotion

h=Planck's constant

c= velocity of light in vacuum

Z= nuclear charge

R=Rydberg constant.

Here Z= 3 for Li++

n1=1 and n2=infinity.