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asked in NEET by (1.9k points)
The ionization  energy of Li++ is equal to

A) 9hcR

B) 6hcR

C) 2hcR

D) hcR

Please  provide  the information  which formulae  of ionization  energy  is used here??

1 Answer

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answered by (9.1k points)
Option A is correct

Explanation

Equation used

∆E=Z^2hcR[1/n1^2-1/n2^2]

Where

∆E ->energy required for promotion

h=Planck's constant

c= velocity of light in vacuum

Z= nuclear charge

R=Rydberg constant.

Here Z= 3 for Li++

n1=1 and n2=infinity.

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